Question

Find the perimeter of a rectangle whose one side measures
10m and the diagonal is 26m.​

Answer 1

This is the answer
Hope it helps

Answer 2

Answer:

the perimeter of the rectangle is 68m

so 1 side measures= 10m

diagonal= 26m

now we can find the unknown side by pythagoras theorem

first take ∆ ACD

the hypotenuse will be=  AD=26m

height will be= AC= x

base will be= CD=10m

now use the pythagoras theorem

hypotenuse^2 = height^2 + base^2

=> 26^2 = x^2 + 100

=> 676 = x^2  + 100

=> 676 - 100 = x^2

=> 576 = x^2

=> x = root576

square root of 576 will be:

(2X2) x (2X2) x (2X2) x (3X3)

make pairs of common numbers and take only one  

= 3 x 2 x 2 x 2 x 2

= 6 x 2 x 2

= 6 x 4

= 24

so x = 24

so the another side is 24m

now we know the length and breadth of the rectangle, let's find the perimeter!

= 2 (L+B)

= 2 (10+24)

= 20 + 48

= 68

so the perimeter of the rectangle is 68m

tried my best to make this clear enough lol hope this helps!!! :D