find the perimeter of a rectangle whose one side measures 20m and the diognal 29m
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Answered by
1
Answer: 82m
Step-by-step explanation:
hypothenuse theorem
29²-20²= 441
√441 = 21m
perimeter
21 + 21 + 20 + 20 = 82m
konerumohanvampb8s11:
How 441 came
for you to find the diagonal, you have to use phytogoras' theorem... a^2+b^2=c^2. the diagonal is given, so a^2=c^2-b^2.
Answered by
1
=perimeter of rectangle=
2*(20+29)
=2*49
= perimeter of rectangle = 98m
2*(20+29)
=2*49
= perimeter of rectangle = 98m
29 is the diagonal
29 is not the length
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