Question

find the perimeter of a rectangle whose perimeter is 146cm and length is 48​

Answer 1

Correct Question :

Find the breadth of a rectangle whose perimeter is 146cm and length is 48.

Given :

• Length $\leadsto$ 48 cm
• Perimeter $\leadsto$ 146 cm

To find :

• We have to find the breadth of Rectangle

Solution :

Let the Breadth be "x" for now :-

⠀

$: \implies \sf 146 \: cm \: = 2 \times (48 + x) \\ \\ \\ : \implies \sf \dfrac{ \cancel{146}}{ \cancel{2}} \: \: \: \: \: = \: \: \: 73 \: cm \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies \sf 73 \: cm = (48 + x) \: cm\\ \\ \\ \: \: \: \: : \implies \sf (73 - 48) cm \\ \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies { \underline{ \boxed{ \pink{ \mathfrak{B \leadsto 25 \: cm}}}}}$

•°• Hence, verified! that the Breadth is

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Answer 2

$\bf\red{Correct~QuestioN:-}$

Find the area of a rectangle whose perimeter is 146 cm and length is 48​ cm.

$\bf\purple{AnsweR:-}$

GiveN:-

Perimeter = 146 cm

Length = 48 cm.

To FinD:-

Area of the rectangle.

SolutioN:-

As we know,

The formula of finding perimeter of a rectangle is

$\pink\bf{:\implies2\times(l+b)}$

That is,

$\pink\bf{:\implies146~cm=2\times(48+b)}$

$\pink\bf{:\implies\dfrac{146}{2}=(48+b)}$

$\pink\bf{:\implies73=(48+b)}$

$\pink\bf{:\implies{73-48=25}}$

$\pink\bf{:\implies{breadth=25~cm}}$

Next step is to find the area.

As we know,

Area of a rectangle =

$\blue\bf{:\implies{area=(l\times{b})}}$

$\blue\bf{:\implies{area=48\times25}}$

$\blue\bf{:\implies{area=1200~cm^2}}$

Hence, the area of the rectangle is 1200 cm^2.