Question

find the perimeter of a rectangle whose width is 5 cm and diagnol is 13 cm​

Answer 1

Answer:Perimeter= 2(l+b)=2(5+13)=36 cm

Answer 2

Correct Question:-⤵️

• Find the perimeter of a rectangle whose width is 5 cm and diagonal is 13 cm.

To Find:-

• The perimeter of a rectangle

Given:-

• Width = 5 cm
• Diagonal = 13 cm

Solution:-

Diagonal = ${BC } ^{2}$ $+CD^{2}$

${13}^{2} = {5}^{2} + CD^{2}$

$CD ^{2} = 169 - 25$

$CD ^{2} = 144$

CD = √144 = 12

Now,

Perimeter of rectangle = 2 (l +b)

Let,

Length = 12 cm

Breadth = 5 cm

=> 2(12 +5)= 2(17) = 34 cm

Answer:- ⤵️

• Hence, the perimeter of rectangle is 34cm.