Question

Find the perimeter of a rectangle with length 12cm and breadth of 5 cm

Answer 1

Answer:

34 CM

Step-by-step explanation:

FOR PERIMITER YOU ADD ALL THE SIDES

P= 12CM+5CM+12CM+5CM

P=34CM

Answer 2

$\underline{\underline{\sf{\maltese\:\:Question}}}$

• Find the perimeter of a rectangle with length 12 cm and breadth of 5 cm

$\underline{\underline{\sf{\maltese\:\:Given}}}$

• Length = 12cm
• Breadth = 5 cm

$\underline{\underline{\sf{\maltese\:\:To\:Find}}}$

• Perimeter of a rectangle

$\underline{\underline{\sf{\maltese\:\:Answer}}}$

• Perimeter of Rectangle = 34 cm

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 12 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 5 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\underline{\underline{\sf{\maltese\:\:Calculations}}}$

Perimeter of Rectangle = 2(Length + Breadth)

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large Length}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large Breadth}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

So we have :

Length = 12 cm

Breadth = 5 cm

Perimeter of Rectangle = 2(Length + Breadth)

⇒ Perimeter of Rectangle = 2(12 cm + 5 cm)

⇒ Perimeter of Rectangle = 2(17 cm)

⇒ Perimeter of Rectangle = 34 cm

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 12 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 5 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$