Find the perimeter of a rectangle with length =24cm and diogonal =25cm.
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l = 24
d = 25 as rectangle each angle is 90° . by pythagoras theorem,
25 x 25 = 24 x 24 + b x b
625 - 576 = b x b
= 49
b ^ 2 = 49
b = √ 49
b = 7 cm
perimeter = 2 (l + b )
= 2 ( 24 + 7 )
= 2 ( 31 )
= 62 cm
Hope this helps you.☺☺☺
d = 25 as rectangle each angle is 90° . by pythagoras theorem,
25 x 25 = 24 x 24 + b x b
625 - 576 = b x b
= 49
b ^ 2 = 49
b = √ 49
b = 7 cm
perimeter = 2 (l + b )
= 2 ( 24 + 7 )
= 2 ( 31 )
= 62 cm
Hope this helps you.☺☺☺
shrifarale:
I'm not understanding it
where u didn't understand , if u tell i will clarify
I understood... thank u
First we will find the width of rectangle by using Pythagorean theorm.
y we should multiply =b x b
hi will u answer a question which i give
yes
Answered by
0
Answer:find
Step-by-step explanation:
Find the width of the rectangle by the using of Pythagorean theorm.
A*A + B*B = C*C
24*24 + B*B = 25*25
B*B = 625-576
B*B = 49
B = 7
Perimeter of rectangle = 2( l + w)
Perimeter of the rectangle = 2(24 + 7)
= 2(31)
62
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