Question

find the perimeter of a rectangular field whose length and breadth are 14 1/2m and 10 2/3 m respectively .​

Answer 1

SOLUTION

TO DETERMINE

The perimeter of a rectangular field whose length and breadth are 14 1/2m and 10 2/3 m respectively

EVALUATION

Here we have to find the perimeter of a rectangular field whose length and breadth are 14 1/2m and 10 2/3 m respectively

So the required perimeter

$\displaystyle \sf{ = 2\bigg( 14 \frac{1}{2} + 10 \frac{2}{3} \bigg) \: \: \: metre}$

$\displaystyle \sf{ = 2\bigg( \frac{29}{2} + \frac{32}{3} \bigg) \: \: \: metre}$

$\displaystyle \sf{ = 2\bigg( \frac{87 + 64}{6} \bigg) \: \: \: metre}$

$\displaystyle \sf{ = \bigg( \frac{151}{3} \bigg) \: \: \: metre}$

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Answer 2

Answer:

SOLUTION

TO DETERMINE

The perimeter of a rectangular field whose length and breadth are 14 1/2m and 10 2/3 m respectively

EVALUATION

Here we have to find the perimeter of a rectangular field whose length and breadth are 14 1/2m and 10 2/3 m respectively

So the required perimeter

\displaystyle \sf{ = 2\bigg( 14 \frac{1}{2} + 10 \frac{2}{3} \bigg) \: \: \: metre}=2(14

2

1

+10

3

2

)metre

\displaystyle \sf{ = 2\bigg( \frac{29}{2} + \frac{32}{3} \bigg) \: \: \: metre}=2(

2

29

+

3

32

)metre

\displaystyle \sf{ = 2\bigg( \frac{87 + 64}{6} \bigg) \: \: \: metre}=2(

6

87+64

)metre

\displaystyle \sf{ = \bigg( \frac{151}{3} \bigg) \: \: \: metre}=(

3

151

)metre