Question

Find the perimeter of a rectangular field whose length and breadth are 16½m and 12¾m respectively.

Answr..
I given 100 points ​

Answer 1

$\color{Purple}{\large\underline{\underline\mathtt{Question:-}}}$

Find the perimeter of a rectangular field whose length and breadth are 16½ m and 12¾ m respectively.

$\color{purple}{\large\underline{\underline\mathtt{To\: find:-}}}$

Perimeter of a rectangular field

$\color{purple}{\large\underline{\underline\mathtt{Given:-}}}$

• Length of the field is 16½ m

• Breadth of the field is 12¾ m

$\color{purple}{\large\underline{\underline\mathtt{Solution:-}}}$

$Length \: of \: the \: field = 16 \frac{1}{2} m \: = \frac{33}{2} m$

$Breadth \: of \: the \: field = 12 \frac{3}{4} m = \frac{51}{4} m$

$⇒Perimeter \: of \: the \: field = 2(length \: \times \: breadth) = 2 \times ( \frac{33}{2} + \frac{51}{4} )m$

$⇒2 \times ( \frac{66}{4} + \frac{51}{4} )m \: = 2 \times ( \frac{66 + 51}{4} )m$

$⇒ (\frac{2}{1} \times \frac{117}{2} )m \: = \frac{117}{2} m = 58\frac{1}{2} m$

$Hence, the \: perimeter \: of \: \: the \: field \: is \: 58\frac{1}{2}m$

$\color{Purple}{\large\underline{\underline\mathtt{Additional\: information:-}}}$

• $0 \: has \: no \: reciprocal$
• $The \: product \: of \: a \: fraction \: and \: its \: reciprocal \: is \: 1.$
• $Product \: of \: two \: fractions = \frac{product \: of \: their \: numerators}{product \: of \: their \: denominators}$
• $Reciprocal \: of \: a \: fraction = \frac{its \: denominator}{its \: numerator}$

Answer 2

Step-by-step explanation:

I think it would be helpful to you