Question

Find the perimeter of a rectangular field whose length and breadth are 33/2 meter and 51/4 meter respectively

Answer 1

Given :-

• A rectangular field whose length and breadth are 33/2 meter and 51/4 meter respectively

To find :-

• Perimeter of a rectangle

Solution :-

• Length of rectangle = 33/2m

• Breadth of rectangle = 51/4 m

As we know that

Perimeter of rectangle = 2(l + b)

Where " l " is length and " b " is breadth of rectangle.

Now, according to question

→ Perimeter of rectangle

→ 2(l + b)

Substitute the values of length and breadth

→ 2(33/2 + 51/4)

→ 2(66 + 51/4)

→ 2 × 117/4

→ 117/2

→ 58.5 m

Hence,

• Perimeter of rectangle = 58.5

Answer 2

AnswEr :-

• Perimeter of the rectangle is 58.5 metres.

Given :-

• Length and breadth of a rectangular field are 33/2m and 51/4m respectively.

To Find :-

• Perimeter of the rectangle.

SoluTion :-

Here,

• Lengh of the rectangle = 33/2m
• Breadth of the rectangle = 51/4m

As we know that perimeter of the rectangle is :-

2 (l + b)

where,

• l = length
• b = breadth

According to question :-

Perimeter = 2 (l + b)

→ 2 {33/2 + 51/4}

→ 2{ (66 + 51)/4 }

→ 2 × 117/4

→ 117/2

→ 58.5

Hence, the perimeter of the rectangle is 58.5 metres.

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