Question

find the perimeter of a rectangular field whose length and breadth are 16 1/2 an d 12 3/4​

Answer 1

Answer:

the perimeter is length = 8

breadth is. = 9

Step-by-step explanation:

explain. =2×(l×d)

=2×( 8×9 )

=2× 72

=144cm. square

Answer 2

Answer:

Perimeter = $\sf{58\dfrac{1}{2}}$

Step-by-step explanation:

Given :

$\sf{Breadth=16\dfrac{1}{2}}$

$\sf{Length=12\dfrac{3}{4}}$

To find :

The perimeter of the rectangular field

Taken :

To find the perimeter use this formula -:

$\boxed{\sf{P=2(L+B)}}$

Where,

P = Perimeter

L = Length

B = Breadth

Solution :

$:\implies\sf{P=2(16\dfrac{1}{2}+12\dfrac{3}{4})}$

Convert it in improper fraction

$:\implies\sf{P=2(\dfrac{33}{2}+\dfrac{51}{4})}$

L.C.M of 2 and 4 is 4

$:\implies\sf{P=2(\dfrac{66+51}{4})}$

$:\implies\sf{P=2\times\dfrac{117}{4}}$

$:\implies\sf{P=\dfrac{\cancel{234}}{\cancel{4}}}$

Covert it in the simplest form

$:\implies\sf{P=\dfrac{117}{2}}$

Convert it in mixed fraction

$:\implies\sf{P=58\dfrac{1}{2}}$

So , the perimeter is $\sf{58\dfrac{1}{2}}$