Math, asked by kajalsihag, 5 months ago

find the perimeter of a rectangular field whose length is 4 times it's width and which has area equal to 20736 sq.m.
please answer correctly
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Answers

Answered by TANI8H
0

720 Is the correct Answer

Is the correct AnswerLet length= 4width

Is the correct AnswerLet length= 4width Area = l × b

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^2

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^2

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4b

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b)

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288)

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360 = 720

Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360 = 720PERMITER OF RECTANGLE IS 720 UNITS

WHILE EDITING EVERYTHING GOT MESSED UP

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