find the perimeter of a rectangular field whose length is 4 times it's width and which has area equal to 20736 sq.m.
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Answers
720 Is the correct Answer
Is the correct AnswerLet length= 4width
Is the correct AnswerLet length= 4width Area = l × b
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^2
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^2
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4b
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b)
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288)
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360 = 720
Is the correct AnswerLet length= 4width Area = l × b20736 = 4b × b20736= 4b^25174 = b^272 = b l = 4bl= 4× 72l = 288Perimeter= 2(l+b) = 2(72+288) =2× 360 = 720PERMITER OF RECTANGLE IS 720 UNITS
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