Question

Find the perimeter of a rectangular field whose length is 4 times its width and which has area equal
to 20736 sq. m.​

Answer 1

Answer:

Let the width be x ,then length is 4x.

We know,

Area of rectangle=l*b

Therefore,area=4x*x

20736=4x^2

144=2x

x=72.

Therefore ,perimeter=2(l+b)

=2(4*72+72)

=2(288+72)

=2*360=720

Answer 2

Answer:

720 m

Step-by-step explanation:

let the width be y m

length = 4y

Area of rectangle = length × breadth

20736 sq. m = 4y × y

20736 sq. m = 4y square.

20736 ÷ 4 = y square

5184 = y square

y = under root of √5184

y = 72 m

so width = 72m

length = 4 ×72 = 288m

Now perimeter of a rectangle =

2× (length + breadth)

2× (288 + 72)

2 × 360

720 m