find the perimeter of a rectangular field whose length is 4 times its widthand which has an area equal to 20736 sq.cm
Answers
Answered by
2
Let the width be x ,then length is 4x.
We know,
Area of rectangle=I*b
Therefore,area=4x*x
20736=4x"2
144=2x
x=72.
Therefore ,perimeter=2(I+b)
=2(4"72+72)
=2(288+72)
=2*360=720
We know,
Area of rectangle=I*b
Therefore,area=4x*x
20736=4x"2
144=2x
x=72.
Therefore ,perimeter=2(I+b)
=2(4"72+72)
=2(288+72)
=2*360=720
thehashtagfever:
thank you so much for answering
Answered by
0
Answer:
Step-by-step explanation:
Let the width be =X
Length=4X
Area=l × b
20736=4X × X
20736=4X2
20736/4=X2
5184=X2
X=72
Perimetr=2l+2b
=2X+2×4X
=2×5X
=10 ×X
=720
CHEERS DONE
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