Question

Find the perimeter of a rectangular field whose length is 4 times its width and which has area equal 20736 sq.m.​

Answer 1

Area of rectangle=l×b

let l=4×b

therefore,Area of rectangle=4b×b

i.e,20736=4b×b

i.e20736/4=b×b

5184=b×b

72uts= b

therefore,l=4×72

therefore l=288

perimeter of rectangle=2(l+b)

=2(72+288)

=2(360)

=720

Answer 2

Hey there! Here is your answer.
Answer is 720m

STEP BY STEP EXPLANATION :
$let \: b \: = x \\\: l \: = 4x \\ = > area = lb \\ = > 20736 = 4x \times x \\ = > 20736 = 4 {x}^{2} \\ = > \frac{20736}{4} = {x}^{2} \\ = > 5184 = {x}^{2} \\ = > \sqrt{5184} = x \\ = > x = 72 \\ hence \: b = 72 \\ \: \ \: \: \: \: \: \: \: \: \: l \: = 4 \times 72 = 288 \\ now \\ perimeter \: = 2( l+ b) \\ = 2(288 + 72) \\ = 2 \times 360 \\ = 720m$
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