Question

Find the perimeter of a rectangular field whose length is three and half tims its breadth. and has an area equal to 32,256 sq cm.

Answer 1

Answer:

Area of a rectangle(A) is given by:

A= l \cdot wA=l⋅w          ....[1]

where l is the length and w is the width of the rectangle respectively.

As per the statement:

Length of rectangle is 4 times its width and which has area equal to 20736 square meters.

⇒l =4wl=4w

Substitute the value of A = 20736 square meter and l =4w in [1] we have;

20736=4w \cdot w20736=4w⋅w  

or

20736 = 4w^220736=4w2

Divide both sides by 4 we have;

5184=w^25184=w2

⇒w = \sqrt{5184}w=5184

Simplify:

w = 72 meter.

then;

l =4(72)=288l=4(72)=288 meter.

Perimeter of rectangle(P) is given by:

P=2(l+w)P=2(l+w)

Substitute the value of l and w we have;

P=2(288+72) = 2(360)=720 cmP=2(288+72)=2(360)=720cm

Therefore, the value of perimeter of a rectangular field is, 720 cm

Step-by-step explanation:

I hope it will help you.

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