Find the perimeter of a rectangular fieldwhose leanth is 4 timesits width and which areais 29636sq.M.
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let the width be x
therefore it length will be 4x
area of rectangle =l×b
= 4x×x=4xsquare
29636÷4=xsquare
7409=Xsquare
X=86
therefore width is 86
And length is 4x86
length is 344
perimeter =2(l+b)
=2(344+86)
=2(430)
=860
therefore perimeter of rectangle is 860
therefore it length will be 4x
area of rectangle =l×b
= 4x×x=4xsquare
29636÷4=xsquare
7409=Xsquare
X=86
therefore width is 86
And length is 4x86
length is 344
perimeter =2(l+b)
=2(344+86)
=2(430)
=860
therefore perimeter of rectangle is 860
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