Question

Find the perimeter of a rectangular park if its length is 200 m and area is 4800 m2. Find
cost of levelling the park at the rate of 1.35 per m2.​

Answer 1

Answer:

breadth of the Park=4800/200

=24m

perimeter of the Park=2(200+24)

2×224

448m

cost of levelling=4800/1.35

=3555.56 rupees

Answer 2

Answer:

Given length of the rectangle = 200m area = 4800m^2

breadth = ??

l × b = area

200× b = 4800

b = 4800/ 200 = 24 m

Perimeter of the rectangle = 2 ( l + b ) = 2 ( 200 + 24) 2 (224 ) = 448 m

cost of levelling the park for per m^2 = 1.35

cost of levelling the park for 4800m2= 4800×1.35 = Rs 6480