Question

find the perimeter of a rectangular park whose lenth and breath are 650m and 1 km respectively​

Answer 1

Answer :

$\large\underline{\frak{\qquad Given : \qquad}}$

• Length of rectangular park = 650 m
• Breadth of rectangular park = 1 km = 1000 m

$\large\underline{\frak{\qquad To\:Find : \qquad}}$

• Perimeter of rectangular park = ?

$\large\underline{\frak{\qquad Solution : \qquad}}$

Note : First of all convert the breadth of rectangle from km to m.

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\textsf{ Perimeter of rectangle = 2(Length + Breadth)}$

$:\implies\textsf {Perimeter of rectangle = 2(650 + 1000)}$

$:\implies\textsf {Perimeter of rectangle = 2(1650)}$

$:\implies \underline{ \boxed{\textsf {Perimeter of rectangle = 3300 m} }}$

$\therefore\:\underline{\textsf{The perimeter of rectangular park is \textbf{3300 m}}}.$

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$\large\underline{\frak{\qquad Formuals \: related \: to \: rectangle : \qquad}}$

• Area of Rectangle = length × breadth
• Perimeter of Rectangle = 2(l+b)
• Diagonal of Rectangle = √(l)² + (b)²

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Answer 2

Given :

• Length of rectangular park = 650 m
• Breadth of rectangular park = 1 km = 1000 m

To Find :

• Perimeter of a rectangular park

Solution :

$\bigstar \: \small {\bf{\underline{\red{Perimeter\:of\:rectangular\:park\:=\:2(l\:+\:b)}}}}$

$\leadsto \small \sf Perimeter\:of\:rectangular\:park\:=\:2(650\:+\:1000)$

$\leadsto \small \sf Perimeter\:of\:rectangular\:park\:=\:2(1650)$

$\bigstar \: \small {\sf{\underline{\red{Perimeter\:of\:rectangular\:park\:=\:3, 300\:m}}}}$

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