Question

find the perimeter of a rectangular whose length is 12 cm and diagonal 13 cm.
solve this question
answer is 34 cm ​

Answer 1

Answer:

Rectangular's length is 12 cm

Rectangular's diagonal is 13 cm

So rectangular's width

={√(diagonal) square-(length) square}cm

={√13 square-12 square}cm

={√169-144}cm

={√25}cm

=5cm

So rectangular's perimeter would be

{2(length+width)}cm

={2(12+5)}cm

={2×17}cm

=34 cm

Answer 2

⛦ Given :

• Length of rectangle = 12cm
• Diagonal of rectangle = 13cm

⛦ To find :

• The perimeter of the rectangle.

⛦ Solution :

To find the value of perimeter of the rectangle , we have to find the value of breadth.

Let's name the rectangle as ABCD

Thus,

• Length = AB = 12cm
• Breadth = AD
• Diagonal = DB = 13cm

Now, finding the value of AD by Pythagorean theorem.

Here, ABD is the triangle

(DB)² = (AB)² + (AD)²

(13)² = (12)² + (AD)²

169 = 144 + (AD)²

(AD)² = 169 - 144

(AD)² = 25

AD = √25

AD = 5cm

Thus,

The value of Breadth of the rectangle is 5cm.

---------------------

Now,

★The perimeter of rectangle = 2(length + breadth)

Perimeter of rectangle = 2 (12 + 5)

Perimeter of rectangle = 2 × 17

Perimeter of rectangle = 34 cm.

Therefore,

The perimeter of rectangle is 34 cm.