find the Perimeter of a regular nonagon with each side measuring 9m
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Answered by
17
it's very simple
as it is a regular nonagon, we just need to multiply the no. of sides in nonagon i.e., 9 to the length of each side i.e., 9m
hence the answer is 9 × 9m= 81m
as it is a regular nonagon, we just need to multiply the no. of sides in nonagon i.e., 9 to the length of each side i.e., 9m
hence the answer is 9 × 9m= 81m
Answered by
7
Given that the length of the each sides of a regular nonagon is 9 cm.
since , we know that
● the all sides of a regular polygon are equal .
●The interior angles of a regular polygon are equal.
●The all exterior angles of a regular polygon are also equal.
●A regular nonagon is a shape having all its 9 sides and angles are equal.
let come to the question :
find the perimeter of regular nonagon having each sides measuring 9 m.
perimeter of regular nonagon
= 9 × side = 9 × 9 = 81 m
therefore,
perimeter of regular nonagon = 81 m
Your Answer : 81 m
_______________________________
since , we know that
● the all sides of a regular polygon are equal .
●The interior angles of a regular polygon are equal.
●The all exterior angles of a regular polygon are also equal.
●A regular nonagon is a shape having all its 9 sides and angles are equal.
let come to the question :
find the perimeter of regular nonagon having each sides measuring 9 m.
perimeter of regular nonagon
= 9 × side = 9 × 9 = 81 m
therefore,
perimeter of regular nonagon = 81 m
Your Answer : 81 m
_______________________________
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