Question

find the perimeter of a rhombus length of whose diagonal are 16 cm and 30 cm respectively .

Answer 1

HEYA MATE, HERE IS UR ANSWER

We know that diagonals bisect each other at 90 degree

Threfore diagonal A / 2=16/2

= 8 cm

Diagonal B/2=30/2

=15 cm

We know that diagonals of rhombus bisect at 90 degree

So by PGT

$\frac {diagonal A}{2}$$^{2}$+$\frac {diagonal B}{2}$$^{2}$= ${side}^{ 2}$

${8}^{2}+{15}^{2}={side }^{2}$

64+225=${side}^{2}$

289=${side}^{2}$

$\sqrt {289}$=side

17cm =side

$\mathbb{Be\:Brainly}$