find the perimeter of a rhombus the length of whose diagonals are 16 cm and 30 cm
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Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD=2DB=216=8cm
and OC=2AC=230=15cm
Now, In right angle triangle DOC,
(DC)2=(OD)2+(CO)2
⇒(DC)2=(8)2+(15)2
⇒(DC)2=64+225=289
⇒DC=289=17cm
Perimeter of the rhombus=4× side
=4×17=68cm
Thus, the perimeter of rhombus is 68 cm.

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