Question

Find the perimeter of a rhombus, the length of whose diagnols are 16 cm and 30 cm

Answer 1

Find the perimeter of a rhombus, the length of whose diagnols are 16 cm and 30 cm

ANSWER--

Now by seeing this attached picture we can say that 8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm...

Since diagonal of a rhombus bisects each other

Now by applying Pythagoras theorem we get,

h² = p² + b²
h² = 8² + 15²
h² = 64 + 225
h² = 289
h = √289
h = 17

Therefore perimeter of the rhombus , 
= 4 × side
= 4 × 17
= 68 cm

Therefore perimeter of the rhombus = 68 cm.

HOPE IT'S HELP YOU...
ANY DOUBTS YOU CAN ASK ME....
THANK YOU...

Answer 2

heya !!
here is your answer

●Given,the measures of diagonals16,30

●We know that diagonals of rhombus are perpendicular bisectors of each other.

db=16

DO=DB/2

DO=16/2

DO=8cm

similarly,AO=15cm

by using pythogaras theorem,

DO²+AO²=DA²

8²+15²=DA²

64+225=DA²

289=DA²

DA=17

perimeter=DA×4
              =17×4
=68CM

i hope it helps