Question

Find the perimeter of a rhombus, the lengths of whose diagonals are
16 cm and 30 cm.
​

Answer 1

Diagonal 1 = 16cm

Diagonal 2 = 30cm

A(Rhombus)=1/2 × product of diagonals

= 1/2×16×30

=240cm^2

Answer 2

Using Pythagoras’ theorem,

Length of one side of rhombus

= square root of [ (16/2)^2 + (30/2)^2 ]

= 17 cm

Since there are 4 sides m, perimeter is

17 x 4 = 68 cm^2



Note that diagonals of a rhombus bisect each other and are perpendicular to each other.


Hope the illustration on the sheet helps.