Question

find the perimeter of a Rhombus who dianogal measure 16cm and 30 cm note the dianogal of a rhoumbus intersecy each other at right angles​

Answer 1

Answer:

side of rohmbus=17cm.

Step-by-step explanation:

(d1) diagonal 1 of rohmbus =16cm

(d2) diagonal 2 of rohmbus =30cm

diagonals of rohmbus bisect each other at 90 degree

taking one right angled triangle from four of them

perpendicular of the triangle =1/2×d1=1/2×16=8cm.

base of the triangle =1/2×d2=1/2×30=15cm.

hypotenuse^=perpendicular ^+base^

(side of rohmbus)^=8^+15^

side of rohmbus =square root of 8^+15^

=square root of 64+225

= square root of 289

= 17

side of rohmbus =17cm.