Find the perimeter of a rhombus whose 2 diagonals are 12 and 16cm
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ANSWER:
PERIMETER OF RHOMBUS IS = 40 CM
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Question:
Find the perimeter of a rhombus whose 2 diagonals are 12cm and 16cm.
Given:
2 Diagonals = 12cm and 16cm
To Find:
It's perimeter.
Solution:
Let a rhombus be ABCD.
Now, It's diagonals met at O. And both are equal.
We know that:
All sides of a rhombus is equal.
By Pythagoras therom, we can find the length of a side.
Let the Δ BOC.
OB= 8cm and OC= 6cm.
Since,
(BC)square = (OB)square + (OC)square
(BC)square = (8×8) + (6×6)
(BC)square = 64+36
(BC)square = 100
BC = √100
BC = 10
Now, It's one side is 10cm.
Perimeter of a rhombus = 4× side.
So, 10×4=40cm.
Since, It's perimeter is 40cm
Answer:
40cm.
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