Question

find the perimeter of a rhombus whose diagonals are 16 cm and 30cm long.​

Answer 1

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Answer:

P=68cm

p Diagonal

16

cm

q Diagonal

30

cm

Using the formulas

P=4a

a=p2+q2

2

Solving forP

P=2p2+q2=2·162+302=68cm

Answer 2

Answer:

Step-by-step explanation:

since diagonal of a rhombus intersect at 90 degree

then by pythagoras theorem,

perimeter= 2 sqrt{p^2*q^2}

therefore perimeter=2$\sqrt{16^2*30^2}$

60 cm