Question

Find the perimeter of a rhombus whose diagonals are 16cm and 12cm​

Answer 1

P = $2\sqrt{p^{2} + q^{2} }$

putting the values.....

$2\sqrt{16^{2} + 12^{2} }$

$2\sqrt{400}$

$2$ × $20$

40... is your answer,,

hope it helps :)

Answer 2

here AC = 16cm

BD = 12cm

Now OA = 16cm / 2 or 8cm

And, OB = 12cm / 2 or 6cm

As we know that diagonal of rhombus bisect at 90°.

H² = P² + B²

AB² = OA² + OB²

AB = √8² + 6²

AB = √64 + 36

AB = √100

AB = 10

THIS IS UR ANSWER