find the perimeter of a rhombus whose diagonals are 6cm and 8 cm respectively
Answers
Answer :
20 cm
Step-by-step explanation :
Diagonal (p) = 6 cm
Diagonal (q) = 8 cm
We know that ;
Perimeter of rhombus = 2 √ p² + q²
= 2 √ 6² + 8²
= 2 √ 36 + 64
= 2 √ 100
= 2 √ 10 * 10
= 2 * 10
= 20 cm
Hence, the perimeter of rhombus is 20 cm .
Answer:
the perimeter of the rhombus is 20 cm.
Step-by-step explanation:
Firstly, let the Rhombus be PQRS, then finding it's length of each side by using Pythagoras Theorem -:
(PQ)² = (OP)² + (OQ)²
(PQ)² = (3)² + (4)²
(PQ)² = 9 + 16
(PQ)² = 25
PQ = √25
PQ = 5 cm
So, length of each side of the given rhombus is 5 cm.
Now, the Perimeter of rhombus = 4 × side
= 4 × 5
= 20 cm
Hence, the perimeter of the rhombus is 20 cm.
hope it helps you friend