find the perimeter of a rhombus whose diagonals Mazhar 12cm and 16 cm respectively
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it is given that ,
length of 1st diagonal = 16 cm
length of 2nd diagonal = 24 cm
area of rhombus = diagonal 1 * diagonal 2/2
therefore area is,
= 16*24/2
= 8*24
= 192 cm^2
so the answer is 192cm^2 which is the area of the given rhombus.
Hope it helpful
length of 1st diagonal = 16 cm
length of 2nd diagonal = 24 cm
area of rhombus = diagonal 1 * diagonal 2/2
therefore area is,
= 16*24/2
= 8*24
= 192 cm^2
so the answer is 192cm^2 which is the area of the given rhombus.
Hope it helpful
jainsulakshya:
This answer is incorrect because you have taken second diagonal as 24cm but it is 12cm...
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