Question

Find the perimeter of a rhombus whose diagonals measure 24 cm and 10 cm.

96cm

40 cm

48 cm

52 cm​

Answer 1

Step-by-step explanation:

Rhombus

Solve for perimeter

P=52cm

p Diagonal

24

cm

q Diagonal

10

cm

Answer 2

lenth of side of rhombus

=$\sqrt{(24/2)^{2}+(10/2)^{2} } }$

=(12^2+5^2)^0.5

=13cm

perimeter=4*l

               =4*13

              =52cm