Question

Find the perimeter of a rhombus whose diagrams are 32 cm and 60cm respectively ​

Answer 1

Answer:

Let ABCD is a rhombus and AC and BD are its diagonals

=4× sides

Side of rhombus:

=

(

2

AC

)

2

+(

2

BD

)

2

=

(

2

24

)

2

+(

2

32

)

2

=

144+256

=

400

=20cm

Therefore perimeter =4×sides =4×20=80cm

Answer 2

Step-by-step explanation:

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