Math, asked by zambezifreightc5623, 7 months ago

Find the perimeter of a rhumbos if the diagonals are 10 cm and 24 cm

Answers

Answered by Anonymous
0

☆Answer☆

Given that

Diagonals of the rhombus = 10cm, 24cm

Diagonals meet at the center and forms right angled triangles. So by using pythagoras theorem

  • Length of the base = 10/2 = 5cm
  • Length of the height = 24/2 = 12cm

Hypotenuse2 = side 2+ side2

= 52+ 122

=25 + 144

= 169

Hypotenuse = 13

Hence the side of the rhombus is 13cm.

Perimeter of the rhombus = 4×side

= 4 × 13

= 52cm.

Therefore, the perimeter of the rhombus is 52cm.

Answered by Anonymous
0

Answer:

52cm

Step-by-step explanation:

Hope it helps

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