Find the perimeter of a rhumbos if the diagonals are 10 cm and 24 cm
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☆Answer☆
Given that
Diagonals of the rhombus = 10cm, 24cm
Diagonals meet at the center and forms right angled triangles. So by using pythagoras theorem
- Length of the base = 10/2 = 5cm
- Length of the height = 24/2 = 12cm
Hypotenuse2 = side 2+ side2
= 52+ 122
=25 + 144
= 169
Hypotenuse = 13
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
Therefore, the perimeter of the rhombus is 52cm.
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Answer:
52cm
Step-by-step explanation:
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