Question

Find the perimeter of a right angle triangle whose hypotenuse is 5 metre long and base and height are equal in length

Answer 1

Answer:

5(1+√2)

hope this will help

Step-by-step explanation:

Let the base and hypotenuse be x

Then by Pythagoras theorem

h^2=p^2+b^2

(5)^2=(x) ^2+(x) ^2

25=2(x)^2

25/2=x^2

5/√2=x

Perimeter = sum of all sides

=5+5/√2+5/√2

=5(1+1/√2+1/√2)

=5(1+2/√2)

=5(1+√2) { by rationalisation }