Question

Find the perimeter of a rombus, the lengths of whose diagonal are 16 cm and 30 cm

Answer 1

HEY DEAR ...

now by seeing this attached picture we can say that 8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm...
since diagonal of a rhombus bisects each other
now by applying Pythagoras theorem we get,
h² = p² + b²
h² = 8² + 15²
h² = 64 + 225
h² = 289
h = √289
h = 17
therefore perimeter of the rhombus , 
= 4 * side
= 4 * 17
= 68 cm
therefore perimeter of the rhombus = 68 cm

HOPE , IT HELPS ...

Answer 2

let the lengths of diagonals

p = 16cm. and q = 30cm

perimeter of rhombus = 2 √( p^2 + q^2 )

= 2 √ ( 16^2 + 30^2 )

= 2 √ ( 256 + 900 )

= 2 √ ( 1156 )

= 2 ×34

= 68 cm

therefore, the perimeter of rhombus

= 68 cm