Question

Find the perimeter of a sector of a circle if its
measure is 90° and radius is 7 cm.​

Answer 1

GIVEN :-

• central angle , ϴ = 90°.
• Radius of circle , r = 7 cm.

TO FIND :-

• Perimeter of sector of Circle.

SOLUTION :-

As we know that , the circumference of a sector of a Circle is given by,

$\\ : \implies \displaystyle \sf \: circumference = 2\pi r \times \frac{ \theta}{360 ^{ \circ} }$

$: \implies \displaystyle \sf \: circumference =2 \times \frac{22}{7} \times 7 \times \frac{90 ^{ \circ} }{360 ^{ \circ} }$

$: \implies \displaystyle \sf \: circumference = \frac{44}{7} \times 7 \times \frac{90 ^{ \circ} }{360 ^{ \circ} }$

$: \implies \displaystyle \sf \: circumference = 44 \times \frac{1}{4}$

$: \implies \underline{ \boxed{\displaystyle \sf \: circumference = 11 \: cm}}$

$\therefore \underline{ \textsf{Perimeter of the Circle is 11 cm.}}$

Answer 2

Answer:

QUESTION

Find the perimeter of a sector of a circle if its

measure is 90° and radius is 7 cm.

GIVEN

• Sector of circle if it's measure 90⁰
• Radius = 7cm

TO FIND

PERIMETER OF SECTOR OF CIRCLE

ANSWER

Circumference = 2πr × ∅/360

$2 \times \frac{22}{7} \times 7 \times \frac{90}{360}$

$\frac{44}{7} \times 7 \times \frac{90}{360}$

$44 \times \frac{1}{4}$

$\huge \fbox {Circumference = 11 cm}$

$\huge \fbox {\red {Perimeter = 11 cm}}$