Question

find the perimeter of a semicircle whose diameter is 35 cm​

Answer 1

GIVEN :-

Diameter of semicircle ( d ) = 35 cm.

TO FIND :-

The perimeter of the semicircle.

SOLUTION :-

As we know that the perimeter of semicircle is given by,

⇒ Perimeter = πr + 2r

⇒ Perimeter = 22/7 × (d/2) + 2 × (d/2)

⇒ Perimeter = 22/7 × 35/2 + 2 × 35/2

⇒ Perimeter = 22 × 5/2 + 35

⇒ Perimeter = 11 × 5 + 35

⇒ Perimeter = 55 + 35

⇒ Perimeter = 90 cm.

Hence perimeter of the semicircle is 90 cm.

Extra Information :-

⇒ Surface area of a cuboid = 2 (lb + bh + hl)

⇒ Surface area of a cube = 6a²

⇒ Curved surface area of a cylinder = 2πrh

⇒ Total surface area of a cylinder = 2πr(r+h)

⇒ Curved surface area of a cone = πrl

⇒ Total surface area of a right circular = πrl + πr²

⇒ Surface area of a sphere = 4πr²

⇒ Curved surface area of a hemisphere = 2πr²

⇒ Total surface area of a hemisphere = 3πr²

⇒ Volume of a cube = a³

⇒ Volume of a cylinder = πr²h

⇒ Volume of a cone = 1/3πr²h

⇒ Volume of a sphere =4/3πr²

⇒ Volume of a hemisphere = 2/3πr²

I hope this is helpful!

Answer 2

Step-by-step explanation:

The perimeter of a semicircle is the sum of the half of the circumference of the circle and diameter. As the perimeter of a circle is 2πr or πd. So, the perimeter of a semicircle is 1/2 (πd) + d or πr + 2r, where r is the radius.

Perimeter = 90 cm. Hence perimeter of the semicircle is 90 cm.