Question

Find the perimeter of a squarc if it's diagonal is


$8 \sqrt{2}$
​

Answer 1

Answer:

Perimeter of square= 4a

Diagonals of square= D=2a

∴a=2162=16∴Perimeter=16×4=64cm

Answer 2

Answer:

let 'a' be the side of square

diagonal=8√2

angle of square=90°

thus

by Pythagoras theorem

(diagonal)²= side²+side²

(8√2)²=2a²

128/2=a²

64=a²

a=8

thus side of square is 8

thus

perimeter=4a

=4×8

=32

thus

perimeter of triangle is 32

thanku

mark as brainlist plz.