Question

find the perimeter of a square having tha same area as that of a rectangle of length 8cm and breath 2cm​

Answer 1

Given:

• Area of square = area of rectangle
• Length of the rectangle = 8 cm
• Breadth of the rectangle = 2 cm

To find:

• Perimeter of the square.

Solution:

Firstly, let's find the area of rectangle, since we are given its dimensions.

$\boxed {\sf {\red {Area\ of\ rectangle = l \times b}}}$

Where,

l = Length

b = Breadth

Substitute the values in the formula,

Area = 8×2

Area of rectangle = 16 cm²

Now, we are given that area of rectangle is equal to the area of square. So,

Area of square = 16 cm²

$\boxed {\sf {\red {Area\ of\ square = s^{2}}}}$

Where,

s = Side

Substitute the values in the formula,

16 = s²

$\sf\sqrt{16} = s$

4 cm = side

Now,

$\boxed {\sf {\red {Perimeter\ of\ square = 4s}}}$

Substitute the values in the formula,

Perimeter = 4×4

$\dag {\boxed {\bf {\pink {Perimeter\ of\ square = 16\ cm}}}}$

Perimeter of square:

Perimeter of the square is 16 cm.