find the perimeter of a square if diagonal is 10 root 2 centimetre
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let ABCD is a square .
AC is a diagonal ,and side = x
so by Pythagoras theorem
(AC)2 = (AB )2 + (BC)2
(10 √2) 2 = X+X
100× 2 = 2x
200÷ 2 = X
X = 100 cm
taking square root
X = 10
perimeter = 4× side
= 4 × 10
= 40
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