Question

find the perimeter of a square ,if its diagonal is
$10 \sqrt{2}$
​

Answer 1

Answer:

plz mark me as brainlist

Answer 2

Answer:

Let the side of the square = a

Let the side of the square = aDiagonal ( d ) = 10√2

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2=> a = 10√2/√2

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2=> a = 10√2/√2a = 10 cm ---( 1 )

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2=> a = 10√2/√2a = 10 cm ---( 1 )Perimeter = 4a

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2=> a = 10√2/√2a = 10 cm ---( 1 )Perimeter = 4aP = 4 × 10

Let the side of the square = aDiagonal ( d ) = 10√2=> √2 a = 10√2=> a = 10√2/√2a = 10 cm ---( 1 )Perimeter = 4aP = 4 × 10P = 40 cm

Step-by-step explanation:

#Hope you have satisfied with this answer...