find the perimeter of a square the sum of length of whose diagonal is 144 CM
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Answer:
Let x be a side of the square and P be the perimeter.
2x² = (144)² ................. Pythagorean theorem
(√2)·x = 144
x = 72√2
P = 4x
P = (4)(72)√2 = 288√2
Answer: P = 288√2 or approx. 407.3 m.....✌✨
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