find the perimeter of a square which diagonal is 12√2
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diagonal=12√2
√2a=12√2
a=12cm(a=side)
perimeter of square=4a
=4×12=48cm
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Answer:
Perimeter = 48 sq.units.
Step-by-step explanation:
Given:
- Diagonal of square = 12√2 units
To find:
Perimeter of square = ?
Solution:
There is a formula which connects Perimeter of square and Diagonal of square which can be derived from Pythagoras theorem i.e.
Perimeter of square = 2√2 × Diagonal
Applying this formula,
Perimeter of square = 2√2 × 12√2
⇒ Perimeter of square = 2 × 12 × √2 × √2
⇒ Perimeter of square = 24 × 2
⇒ Perimeter of square = 48 sq.units.
∴ Perimeter of square = 48 sq.units.
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