Question

find the perimeter of a square whose area is 1024

Answer 1

Answer:

area =side^2

area = 1024

side =√1024

side =32

perimeter =4(side)

perimeter =4x32

perimeter =128

Answer 2

Your Answer:

Given:-

• Area of Square = 1024units^2

To find:-

• Perimeter of Square

Solution:-

We have area of Square

So,

$\tt \large\blue \bf {s^2=1024}$

where 's' is the side of Square

$\tt s = \sqrt{1024} \\\\ \tt \Rightarrow s = \sqrt{32\times 32} \\\\ \tt \Rightarrow s= 32\:units$

Now we have side of the Square

So,

$\tt Perimeter\: of\: Square=4s \\\\ \tt \Rightarrow Perimeter = 4(32)units \\\\ \tt \Rightarrow Perimeter = 128units$

So, perimeter of Square is 128units