Question

find the perimeter of a square whose area is 324 cm²​

Answer 1

Answer:

perimeter of square = 4 s

324=4S

s= 324/4

S = 81

Answer 2

Step-by-step explanation:

Question :-

• Find the perimeter of square whose area is 324 cm².

To Find :-

• Perimeter of square.

Solution :-

Given :

• Area = 324 cm²

According to the question,

By using the formula,

${\sf{\longrightarrow Area\ of\ square\ =\ a^2}}$

Where,

• a = length of the side

Finding side of square :

${\sf{\longrightarrow Area\ of\ square\ =\ a^2}}$

${\sf{\longrightarrow 324\ =\ a^2}}$

${\sf{\longrightarrow \sqrt{324}\ =\ a}}$

${\sf{\longrightarrow 18\ =\ a}}$

${\sf{\longrightarrow a\ =\ 18\ cm}}$

Now, let's find the perimeter of square.

$\rule{300}{2}$

By using the formula,

${\sf{\longrightarrow Perimeter\ of\ square\ =\ 4a}}$

Where,

• a = length of the side

Finding perimeter of square :

${\sf{\longrightarrow Perimeter\ of\ square\ =\ 4a}}$

${\sf{\longrightarrow 4(18)}}$

${\sf{\longrightarrow 4 \times 18}}$

${\sf{\longrightarrow 72\ cm}}$

$\therefore$ Hence, perimeter of square is 72 cm.

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$