find the perimeter of a square whose diagonal is 12 centimetre
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diagonal=12
=√2×bhuja
so, 12/√2=bhuja
bhuja=6√2
so,perimeter=4×bhuja
=4×6√2=24√2ans
=√2×bhuja
so, 12/√2=bhuja
bhuja=6√2
so,perimeter=4×bhuja
=4×6√2=24√2ans
Answered by
3
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here is your answer
⇒diagonal of the square is 8√2
⇒8√2= 12
⇒8= 12/√2
make this into simplest form
⇒8= 12/√2 * √2/√2
⇒ 12 √2/√4
⇒12 √2/2
⇒ 6√2
⇒ perimeter of the square is 4s
⇒ 4 ( 6√2) ⇒ 24√2
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hope this helped u a lot
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