Question

Find the perimeter of a square whose diagonal is 12 root 2cm​

Answer 1

Answer:

Diag. of square = √2 a

                         √2 a = (12 / √2) cm

                               a = 6 cm

Step-by-step explanation:

hence ,

        Perimeter of sq.= 4 a

                                  = 4 (6) cm

                                   = 24 cm

And,

         Area of Square= a²

                                   =(6)² cm

                                   =36 cm²

I hope it helps.

Answer 2

Answer:

area of square= d * d / 2

where d is the diagonal

here d=12 \sqrt{2} \: cm

$\\ area = \frac{12 \sqrt{2} \times 12\sqrt{2} }{2} \\ = \frac{288}{2} = 144$