Question

FIND THE PERIMETER OF A SQUARE WHOSE DIAGONAL IS 16 CM. If you answer correctly, you will get a brainliest

Answer 1

Answer:

the diagonals of a triangle bisects each other

$1 \div 2 \times 16$

=8

= By pythagorus theorem

8^2 + 8^2 = hypotenuse^2

64+64=

$\sqrt{128}$

=one of the aide of square=

$8 \sqrt{2}$

=perimeter of square=

$4 \times 8 \sqrt{2}$

=

$32 \sqrt{2}$

this is your answer.

i hope it is right