Question

find the perimeter of a square whose diagonal is 7√2 cm long

Answer 1

side of sq =1√2*diagonals = 1/√2*7√2=7cm

perimeter = 4×side=4*7=28cm

Answer 2

Answer:

$Perimeter(P)=28\:cm$

Step-by-step explanation:

Let a and d are side and diagonal of a square.

$Diagonal (d) = 7\sqrt{2}\:cm$

$\sqrt{2} a=7\sqrt{2}$

$\implies a = \frac{7\sqrt{2}}{\sqrt{2}}\\=7\:cm$

$side \:of\:the \: square (a)=7\:cm$

$Now,\\Perimeter(P)=4a\\=4\times 7\:cm \\=28\:cm$

Therefore,

$Perimeter(P)=28\:cm$

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