Find the perimeter of a triangle ABC where AB=11/4,BC=24/5,AC=63/8
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To find the perimeter of \triangle ABC we use the Pythagorean Theorem which tells us that
|AB|^2 = |AC|^2 + |BC|^2.
Since |AC| = 5 and |BC| = 12
we find that |AB| = \sqrt{169} = 13. The perimeter of \triangle ABC is then 5 + 12 + 13 = 30 units.
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